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Chemistry Question on Equilibrium

The hydrogen ion concentration of a 10−8MHCl10^{-8}M HCl aqueous solution at 298 K (Kw=10−14)( K_w = 10^{-14} ) is :-

A

1.0×10−6M1.0 \times 10^{-6} M

B

1.0525×10−7M1.0525 \times 10^{-7} M

C

9.525×10−8M9.525 \times 10^{-8} M

D

1.0×10−8M1.0 \times 10^{-8} M

Answer

1.0525×10−7M1.0525 \times 10^{-7} M

Explanation

Solution

[H+]=10−8 M\left[ H ^{+}\right]=10^{-8} \,M Due to dilute solution. [H+]=10−8+10−7M\left[ H ^{+}\right] =10^{-8}+10^{-7} M =10−7[0.1+1]M=10^{-7}[0.1+1] M =1.1×10−7M=1.1 \times 10^{-7} M =1.1×10−7M=1.1 \times 10^{-7} M ≃1.0525×10−7 M \simeq 1.0525 \times 10^{-7}\, M