Question

The hybridized state of $Al^{3+}$ in the complex ion formed when $AlCl_3$ is treated with aqueous acid is

• A. $sp^3$
• B. $dsp^2$
• C. $sp^3d^2$
• D. $sp^2d$

Answer 1

Answer: (C)

$sp^3d^2$

Answer 2

$AlCl _{3}+$ aqueous acid $\rightarrow\left[ Al \left( H _{2} O \right)_{6}\right]^{3+}$ $Al ^{3+}$ ions give a complex ion in which $Al ^{3+}$ ion form six coordinate covalent bonds with six $H _{2} O$ molecules. Hence, it shows $s p^{3} d^{2}$ hybridisation. (Due to availability of vacant $3 d$ -orbitals.) $A l=3 s^{2} 3 p^{1}$ $A l^{3 T}=3 s^{0}$ Four electron pairs denoted by $6H_{2}O$ molecules