Question

The hybridization involved in $PCl_5$ is

• A. $sp^{3}d$
• B. $sp^{3}d^{2}$
• C. $d^{2}sp^{2}$
• D. $sp^{3}$

Answer 1

Answer: (A)

$sp^{3}d$

Answer 2

In $PCl _{5}$ five chlorine atoms directly attached to central atom and it has no Ione pairs and no single electrons hence $PCl _{5}$ has $sp ^{3} d$ hybridization.