Question

The hybridisation of atomic orbital of nitrogen in $NO_2^{+}, NO_{3}^{-}$ and $NH_{4}^{+}$ are respectively

• A. $sp, sp^2, sp^3$
• B. $sp^2, sp^3,sp$
• C. $sp^2, sp , sp^3$
• D. $sp^2d, sp^3, sp$

Answer 1

Answer: (A)

$sp, sp^2, sp^3$

Answer 2

Nitronium ion $(NO_2^{+})$ Hybridisation $= sp$ Geometry $=$ linear Nitrate $(NO_3^-)$ Hybridisation $= sp^2$ Geometry $=$ trigonal planar Ammonium ion $(NH_4^+)$ Hybridisation $= sp^3$ Geometry $=$ tetrahedral