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Question

Physics Question on projectile motion

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is

A

00^{\circ}

B

3030^{\circ}

C

4545^{\circ}

D

6060^{\circ}

Answer

4545^{\circ}

Explanation

Solution

Given H=4RH = 4R u2sin2θg=4×u2sin2θ2g\therefore \:\:\: \frac{u^2 \, \sin \, 2 \theta}{g} = 4 \times \frac{u^2 \, sin^2 \theta}{2g} or tanθ=1\tan \, \theta = 1 or θ=45\theta = 45^\circ