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Question: The horizontal component of the earth’s magnetic field at a place is 3 × 10<sup>–4</sup>T and the di...

The horizontal component of the earth’s magnetic field at a place is 3 × 10–4T and the dip is tan⁡−1(43)\tan ^ { - 1 } \left( \frac { 4 } { 3 } \right). A metal rod of length 0.25 m placed in the north-south position and is moved at a constant speed of 10 cm/s towards the east. The emf induced in the rod will be

A

Zero

B

1μV

C

5 μV

D

10 μV

Answer

10 μV

Explanation

Solution

Rod is moving towards east, so induced emf across it’s end will be e = BVvl

BV = vertical component of Earth’s magnetic field = BH tanφ (BH – horizontal component of earth’s magnetic field; φ – angle of dip), BV=3×10−4×43=4×10−4 TB _ { V } = 3 \times 10 ^ { - 4 } \times \frac { 4 } { 3 } = 4 \times 10 ^ { - 4 } \mathrm {~T}

∴