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Question: The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4...

The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. Is

A

tan1(1)\tan ^ { - 1 } ( 1 )

B

tan1()\tan ^ { - 1 } ( \infty )

C

tan1(1.518)\tan ^ { - 1 } ( 1.518 )

D

tan1(π)\tan ^ { - 1 } ( \pi )

Answer

tan1(1.518)\tan ^ { - 1 } ( 1.518 )

Explanation

Solution

By using BH=BcosϕB _ { H } = B \cos \phi

cosϕ=BHB=0.220.4\cos \phi = \frac { B _ { H } } { B } = \frac { 0.22 } { 0.4 }

tanϕ=(0.4)2(0.22)20.22\tan \phi = \frac { \sqrt { ( 0.4 ) ^ { 2 } - ( 0.22 ) ^ { 2 } } } { 0.22 }

ϕ=tan1(1.518)\phi = \tan ^ { - 1 } ( 1.518 )