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Physics Question on Types of Magnets

The horizontal component of the earth?s magnetic field is 3.6×10−53.6 \times 10^{-5} tesla where the dip angle is 60∘60^{\circ}. The magnitude of the earth?s magnetic field is

A

2.8×10−4 tesla2.8\times10^{-4}\,tesla

B

2.1×10−4 tesla2.1\times10^{-4}\,tesla

C

7.2×10−5 tesla7.2\times10^{-5}\,tesla

D

3.6×10−5 tesla3.6\times10^{-5}\,tesla

Answer

7.2×10−5 tesla7.2\times10^{-5}\,tesla

Explanation

Solution

Horizontal component of earth?s field,
H=Bcos θ,H = Bcos\,\theta, since, θ=60∘\theta = 60^{\circ}
3.6×10−5=B×12⇒ B=7.2×10−5 Tesla3.6\times10^{-5} = B\times\frac{1}{2} \Rightarrow \,B = 7.2\times10^{-5} \,Tesla