Solveeit Logo
Login

Question

Physics Question on the earth's magnetic field

The horizontal component of Earth’s magnetic field at a place is 3 × 10-5 T. If the dip at that place is 45°, the resultant magnetic field at that place is

A

32×10−5 T\frac{3}{\sqrt2}\times10^{-5}\ T

B

323×10−5 T\frac{3}{2}\sqrt3\times10^{-5}\ T

C

32×10−5 T3\sqrt2\times10^{-5}\ T

D

3×10−5 T3\times10^{-5}\ T

Answer

32×10−5 T3\sqrt2\times10^{-5}\ T

Explanation

Solution

The correct answer is (C) : 32×10−5 T3\sqrt2\times10^{-5}\ T.