Question

The Henry’s law constant (KH) values of three gases (A, B, C) in water are 145, 2 × 10–5 and 35 kbar, respectively. The solubility of these gases in water follow the order :

• A. B > A > C
• B. B > C > A
• C. A > C > B
• D. A > B > C

Answer 1

Answer: (B)

B > C > A

Answer 2

1. Solubility is inversely proportional to $K_H$. Lower $K_H$ implies higher solubility.
2. $K_H$ values: A = 145, B = $2 \times 10^{-5}$, C = 35.
3. Order of solubility: B (lowest $K_H$) > C > A.