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Question: The height of a mercury barometer is \[75cm\] at sea level and \[50cm\] at the top of a hill a . Rat...

The height of a mercury barometer is 75cm75cm at sea level and 50cm50cm at the top of a hill a . Ratio of density of mercury to that of air is 104{10^4}. The height of the hill is-
A. 1.25Km1.25Km
B. 2.5Km2.5Km
C. 250m250m
D. 750m750m

Explanation

Solution

A mercury barometer is a device that is used to measure the atmospheric pressure at a given location. As, ratio of density of mercury to that of the air, ρHgρAir\dfrac{{{\rho _{Hg}}}}{{{\rho _{Air}}}} is given=104{10^4}. We know the equation for the change in pressure. By substituting all the given values, we can easily find the value of the height, h.

Formula used:
Δp=(h1h2)×ρHg×g\Delta p = \left( {{h_1} - {h_2}} \right) \times {\rho _{Hg}} \times g
Here Δp\Delta p is the change in pressure,h1{h_1} and h2{h_2} are the heights of
barometer, g is gravity and ρHg{\rho _{Hg}} is the density of mercury.

Complete step by step answer:
As we know that the pressure difference between the sea level and the top of hill is-
Δp=(h1h2)×ρHg×g\Delta p = \left( {{h_1} - {h_2}} \right) \times {\rho _{Hg}} \times g ---- (1)
h1{h_1} and h2{h_2} are the heights of mercury barometer- given- 75cm75cm and 50cm50cm respectively. Now substitute all the values in the equation (1), we get-
Δp=(h1h2)×ρHg×g\Delta p = \left( {{h_1} - {h_2}} \right) \times {\rho _{Hg}} \times g
Δp=(7550)×102×ρHg×g\Rightarrow\Delta p = \left( {75 - 50} \right) \times {10^{ - 2}} \times {\rho _{Hg}} \times g --- (2)
Pressure difference due to h metre of air-Δp=h×ρAir×g\Delta p = h \times {\rho _{Air}} \times g-- (3)

Equate equation (2) and (3), we get-
h×ρAir×gh \times {\rho _{Air}} \times g=(7550)×102×ρHg×g\left( {75 - 50} \right) \times {10^{ - 2}} \times {\rho _{Hg}} \times g
For finding the height of the hill, h we can take all terms on the right hand side, we get-
ρHgρAir×25×102\dfrac{{{\rho _{Hg}}}}{{{\rho _{Air}}}} \times 25 \times {10^{ - 2}}
Now we know the ratio of density of mercury to the air is already given in this question,
h=104×25×102\therefore h = {10^4} \times 25 \times {10^{ - 2}}
So, the height of the hill comes out to be 2500m2500mor 2.5Km2.5Km .

Hence, option B is correct.

Note: A mercury barometer is a device that is used to measure the atmospheric pressure at a given location. The barometer consists of a vertical glass tube which is closed at one end. Additionally, The air around us has weight, and it presses against everything it touches. That pressure is known as atmospheric pressure.