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Question

Physics Question on Gravitation

The height of a geostationary satellite is

A

1000 km

B

32000 km

C

36000 km

D

850 km

Answer

36000 km

Explanation

Solution

A satellite which revalues around the earth in its equatorial plane with the same angular speed and in the same direction as the earth rotates about its own axis is called a geostationary or synchronous satellite. The height of a satellite above the earth's surface is given by h=(T2R2g4π2)1/3Rh=\left(\frac{T^2R^2g}{4\pi^2}\right)^{1/3} -R But T = 24 h = 86400 s R = radius of earth = 6400 km g=9.8ms2=0.0098kms2g=9.8 ms^{-2}=0.0098 kms^{-2} = h=((86400)2×(6400)2×0.00984×9.87)1/3h=\left(\frac{(86400)^2\times(6400)^2\times0.0098}{4\times9.87}\right)^{1/3} d = 42330 - 6400 = 35930 km = 36000 km