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Question

Physics Question on Gravitation

The height at which the weight of a body becomes 1/16th 1 / 16^{\text {th }}, its weight on the surface of earth (radius R), is

A

5R

B

15R

C

3R

D

4R

Answer

3R

Explanation

Solution

WhW=mgmg=(RR+h)2=116\frac{ W _{ h }}{ W }=\frac{ mg }{ mg }=\left(\frac{ R }{ R + h }\right)^{2}=\frac{1}{16}
h=3R\therefore h =3\, R