Solveeit Logo

Question

Chemistry Question on Enthalpy change

The heats of combustion of carbon and carbon monoxide are 393.5-393.5 and 283.5kJmol1-283.5 \, kJ \, mol^{-1}, respectively. The heat of formation (in kJkJ) of carbon monoxide per mole is :

A

110.5

B

676.5

C

-676.5

D

-110.5

Answer

-110.5

Explanation

Solution

C(g)+O2(g)CO2(g)ΔH1=393.5kJ/molC _{( g )}+ O _{2( g )} \longrightarrow CO _{2( g )} \,\,\,\,\,\,\,\, \Delta H _{1}=-393.5\, kJ /\, mol CO(g)+12O2(g)CO2(g)ΔH2=283.5kJ/molCO _{( g )}+\frac{1}{2} O _{2( g )} \longrightarrow CO _{2}( g ) \,\,\,\,\,\,\,\, \Delta H _{2}=-283.5\, kJ /\, mol C(g)+12O2(g)CO(g)ΔH=ΔH1ΔH2=110kJ/molC _{( g )}+\frac{1}{2} O _{2( g )} \longrightarrow CO _{( g )} \,\,\,\,\,\,\,\,\Delta H =\Delta H _{1}-\Delta H _{2}=-110 \,kJ\, / mol