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Question: The heat of transition \(H_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow H_{2}O(l)\Delta G^{o} = - 237kJ\...

The heat of transition H2(g)+12O2(g)H2O(l)ΔGo=237kJH_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow H_{2}O(l)\Delta G^{o} = - 237kJ of graphite into diamond would be, where

H2(g)+2C(s)C2H2(g)H_{2}(g) + 2C(s) \rightarrow C_{2}H_{2}(g)

A+BC+DA + B \equiv C + D.

A

moleL1moleL^{- 1}

B

300K300K

C

ΔG\Delta G

D

None of these

Answer

300K300K

Explanation

Solution

Graphite 298K298Kdiamond 382.64kJmol1- 382.64kJmol^{- 1}.