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Question: The heat of transition for carbon from the following is C<sub>Diamond</sub> + O<sub>2</sub>(g) → C...

The heat of transition for carbon from the following is

CDiamond + O2(g) → CO2(g) ∆H = – 94.3 kcal

CAmorphous+ O2(g) → CO2(g) ∆H = – 97.6 kcal

A

3.3 kJ / mol

B

3.3 kcal / mol

C

–3.3 kJ / mol

D

– 3.3 kcal / mol

Answer

3.3 kcal / mol

Explanation

Solution

Given

CD + O2(g) → CO2(g)

∆H = –94.3 kcal …(1)

CA + O2(g) → CO2(g)

∆H = – 97.6 kcal …(2)

– – – +

Subtracting equation (2) from equation (1):

CD – CA → 0; ∆H = +3.3 kcal

CD → CA ∆H = +3.3 kcal