Question

The heat of neutralization of a strong base and a strong acid is $57 kJ .$ The heat released when $0.5$ mole of $HNO _{3}$ solution is added to $0.20 moles$ of $NaOH$ solution, is

• A. 11.4 kJ
• B. 34.7 kJ
• C. 23.5 kJ
• D. 58.8 kJ

Answer 1

Answer: (A)

11.4 kJ

Answer 2

Heat of neutralization $(\Delta H)=57\, kJ$, mole of $HNO 3=0.5$ mole and mole of $NaOH =0.2$ mole. When $HNO _{3}$ solution is added to $NaOH$ solution, then $0.2$ mole of $HNO _{3}$ solution will combine with $0.2$ mole of $OH ^{-}$ ions of $NaOH$ solution. $\therefore$ Heat released $=\Delta H \times 0.2=57 \times 0.2=11.4 \,kJ .$