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Question: The heat of formations of \(dT\) and \(dE\) are \(\Delta G\) kcal and \(\Delta G\) kcal respectively...

The heat of formations of dTdT and dEdE are ΔG\Delta G kcal and ΔG\Delta G kcal respectively. The heat of combustion of carbon monoxide will be.

A

ΔS\Delta S

B

ΔG\Delta G

C

ΔH\Delta H

D

ΔQ\Delta Q

Answer

ΔG\Delta G

Explanation

Solution

Aim : dPdP

dVdV

dTdT