Solveeit Logo

Question

Chemistry Question on Thermodynamics terms

The heat of formation of water is 260kJ260\, kJ . How much H2OH_2O is decomposed by 130kJ130\, kJ of heat ?

A

0.25mol0.25\, mol

B

1mol1\, mol

C

0.5mol0.5\, mol

D

2mol2\, mol

Answer

0.5mol0.5\, mol

Explanation

Solution

The reaction for the formation of water is as

H2+12O2H2OH _{2}+\frac{1}{2} O _{2} \to H _{2} O ; ΔH=260kJ(i)\Delta H=260 kJ\, \ldots (i)

On reversing E (i), we get

H2O1 molH2+12O2\underset{\text{1 mol}}{H_{2}O} \to H_{2}+\frac{1}{2} O_{2};

ΔH=260kJ(ii)\Delta\, H=-260 \,kJ \, \dots(ii)
\because By 260kJ260 \,kJ heat water decomposed =1mol=1 \,mol
130kJ\therefore 130\, kJ heat will decompose water =1×130260=\frac{1 \times 130}{260}
=0.5mol=0.5 \,mol