Question
Chemistry Question on Enthalpy change
The heat of formation of CO(g) and CO2(g) are ΔH=−110 and ΔH=−393kJmol−1 respectively. What is the heat of reaction (ΔH) (in kJmol−1) for the following reaction? CO(g)+21O2(g)CO2(g)
A
−504
B
−142.5
C
−283
D
504
Answer
−283
Explanation
Solution
C+21O2CO,ΔH=−110kJmol−1 ? (i) C+O2CO2,ΔH=−393kJmol−1 ... (ii) On subtracting Eq (i) from eq (ii), we get CO+21O2CO2 ΔH=393−(−110) =−283kJmol−1