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Question

Chemistry Question on Enthalpy change

The heat of formation of CO(g)CO(g) and CO2(g)C{{O}_{2}}(g) are ΔH=110\Delta H=-110 and ΔH=393kJmol1\Delta H=-393\,\,kJ\,\,mo{{l}^{-1}} respectively. What is the heat of reaction (ΔH)(\Delta H) (in kJmol1)kJ\,\,mo{{l}^{-1}}) for the following reaction? CO(g)+12O2(g)CO2(g)CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g)

A

504-504

B

142.5-142.5

C

283-283

D

504504

Answer

283-283

Explanation

Solution

C+12O2CO,ΔH=110kJmol1C+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}CO,\,\,\Delta H=-110\,\,kJ\,\,mo{{l}^{-1}} ? (i) C+O2CO2,ΔH=393kJmol1C+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}},\,\,\Delta H=-393\,\,kJ\,\,mo{{l}^{-1}} ... (ii) On subtracting Eq (i) from eq (ii), we get CO+12O2CO2CO+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}C{{O}_{2}} ΔH=393(110)\Delta H=393-(-110) =283kJmol1=-283\,\,kJ\,\,mo{{l}^{-1}}