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Question

Chemistry Question on Chemical bonding and molecular structure

The heat of formation of CO2C{{O}_{2}} is 95 kcal-95\text{ }kcal . The amount of carbon which on burning will evolve 1000 kcal is

A

12.63 g

B

17.95 g

C

126.3 g

D

179.5 g

Answer

126.3 g

Explanation

Solution

C(s)+O2(g)CO2(g)C(s)+{{O}_{2}}(g)\xrightarrow[{}]{{}}C{{O}_{2}}(g) ΔHfo(CO2)= 95 kcal mol1\Delta H_{f}^{o}(C{{O}_{2}})=-\text{ }95\text{ }kcal\text{ }mo{{l}^{-1}} =95=-95 kcal/12g of carbon Thus, carbon required for 1000 kcal of heat =12×100095=\frac{12\times 1000}{95} =126.3g=126.3g