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Question: The heat of combustion of carbon to \( C{O_2} \) is \( - 393.5KJ/mol \) . The heat released upon for...

The heat of combustion of carbon to CO2C{O_2} is 393.5KJ/mol- 393.5KJ/mol . The heat released upon formation of 35.2g35.2g CO2C{O_2} from carbon and oxygen gas will be.
(A) 315  KJ- 315\;KJ
(B) +315  KJ+ 315\;KJ
(C) 630  KJ- 630\;KJ
(D) +31.5  KJ+ 31.5\;KJ

Explanation

Solution

The heat of combustion of a substance is defined as the amount of heat released when the given amount of a substance undergoes a combustion reaction. The enthalpy change for the combustion reaction is always negative. With the help of the reaction enthalpies we can easily calculate the heat released on the formation of carbon dioxide.

Complete step by step answer:
Now we are aware about the basic concept of heat of combustion or the enthalpy of combustion both represents the amount of energy required for the combustion of substance. Now we will get back to our question. So , the question says that the heat of combustion of carbon to CO2C{O_2} is 393.5KJ/mol- 393.5KJ/mol . So, now we will understand the given quantities so we have given the heat or the enthalpy of combustion that is (ΔH)=393.5KJ/mol(\Delta H) = - 393.5KJ/mol . Now we will write the reaction for the heat of combustion of carbon to carbon dioxide. So according to the question the reaction will be C+O2CO2C + {O_2} \to C{O_2} . So according to the reaction we have given the heat of combustion for 11 mole of . CO2C{O_2} . Now if we calculate the number of moles in 35.2g35.2g of CO2C{O_2} we can easily calculate the heat released. So, the moles of CO2=35.244=0.8moleC{O_2} = \dfrac{{35.2}}{{44}} = 0.8mole the molar mass of CO2C{O_2} is 44g/mol44g/mol . Now we can easily calculate the heat of combustion for 0.8mole0.8mole of CO2C{O_2} which is 393.5×8=315KJ- 393.5 \times 8 = - 315KJ .
Therefore, the correct option is (A).

Note:
The heat of combustion is always negative as they are the exothermic reactions. Exothermic reactions are the reactions in which heat is released therefore the calculated heat is negative. The temperature change affects the heat of combustion.