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Question: The heat is flowing through a rod of length 50 cm and area of cross-section 5cm<sup>2</sup>. Its end...

The heat is flowing through a rod of length 50 cm and area of cross-section 5cm2. Its ends are respectively at 250C and 1250C. The coefficient of thermal conductivity of the material of the rod is 0.092 kcal/m×s×0C. The temperature gradient in the rod is

A

2 0C / cm

B

2 0C / m

C

20 0C / cm

D

10 0C /m

Answer

2 0C / cm

Explanation

Solution

Temperature gradient

=ΔθΔx=θ2θ1Δx=1252550=2oC/cm= \frac{\Delta\theta}{\Delta x} = \frac{\theta_{2} - \theta_{1}}{\Delta x} = \frac{125 - 25}{50} = 2^{o}C/cm.