Question

The heat dissipated (I2Rt) in a resistance can be obtained by the measurement of resistance, current and time. If the maximum percentage error in the measurement of these quantities is 1%, 2%, and 1% respectively. The maximum percentage error in the determination of the dissipated heat is 002D

• A. (a) 4%
• A. (b) 6%
• A. (c) 4/3%
• A. (d) 2%

Answer 1

(b)

Sol. $\frac { \Delta \mathrm { H } } { \mathrm { H } }$ × 100 = $\frac { 2 \Delta \mathrm { I } } { \mathrm { I } }$ × 100 + $\frac { \Delta \mathrm { R } } { \mathrm { R } }$ × 100 + $\frac { \Delta \mathrm { t } } { \mathrm { t } }$ × 100

= 2 × 2% + 1% + 1% = 6%