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Question

Physics Question on kinetic theory

The heat capacity per mole of water is (RR is universal gas constant)

A

9R9R

B

92R\frac{9}{2}R

C

6R6R

D

5R5R

Answer

9R9R

Explanation

Solution

Molar specific heat of water = molar mass of water ×\times specific heat of water =18gmol×1calgoC=\frac{18g}{mol}\times \frac{1\,cal}{{{g}^{o}}C} =18calmoloC=18\frac{cal}{mo{{l}^{o}}C} =9R=9R [where, R=2 cal mol2o C1R=2\text{ }cal\text{ }mo{{l}^{-{{2}_{o}}}}\text{ }{{C}^{-1}} ]