Question

The heat absorbed by a system in going through the given cyclic process is :

• A. 61.6 J
• B. 431.2 J
• C. 616 J
• D. 19.6 J

Answer 1

Answer: (A)

61.6 J

Answer 2

For a cyclic process, the change in internal energy ($\Delta U$) is zero. Therefore, the heat absorbed ($\Delta Q$) is equal to the work done ($\Delta W$), which is the area enclosed by the P-V curve. The area is calculated as:

$\Delta Q = \Delta W = \pi \times (140 \times 10^3) \, \text{Pa} \times (140 \times 10^{-6} \, \text{m}^3)$

$\Delta Q = 61.6 \, \text{J}$