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Question: The half-life period of \({{N}^{13}}\) is 10.1 minute. Its mean lifetime is: A. 5.05 minutes B. ...

The half-life period of N13{{N}^{13}} is 10.1 minute. Its mean lifetime is:
A. 5.05 minutes
B. 20.2 minutes
C. 10.10.6931\dfrac{10.1}{0.6931} minutes
D. Infinity

Explanation

Solution

Hint : Half-life period of an element is the time in which the number of radioactive nuclei decay is half of its initial value. Mean life of all nuclei of radioactive elements is the mean total life of all nuclei. There is a relation between mean life and half – life i.e. τ=thalf0.693\tau =\dfrac{{{t}_{half}}}{0.693}. Therefore we can find mean life directly from this formula. Let us see in brief how this formula came.

Complete step by step answer:
We know that from radioactive decay equation,
N=N0eλtN={{N}_{0}}{{e}^{-\lambda t}}
Where:
NNis number of nuclei at time t
N0{{N}_{0}} is the number of nuclei at t=0 or number of nuclei in the beginning
λ\lambda is the decay constant.
Decay constant of a radioactive element is defined as the reciprocal of time, the number of undecayed nuclei of that radioactive element falls to 1e\dfrac{1}{e} times of its initial value.
For half-life,
t=t12 N=N02 N02=N0eλt \begin{aligned} & t={{t}_{\frac{1}{2}}} \\\ & N=\dfrac{{{N}_{0}}}{2} \\\ & \dfrac{{{N}_{0}}}{2}={{N}_{0}}{{e}^{-\lambda t}} \\\ \end{aligned}
Taking log on both sides,
loge2=λt12 t12=loge2λ t12=0.693λ \begin{aligned} & {{\log }_{e}}2=\lambda {{t}_{\frac{1}{2}}} \\\ & {{t}_{\frac{1}{2}}}=\dfrac{{{\log }_{e}}2}{\lambda } \\\ & {{t}_{\frac{1}{2}}}=\dfrac{0.693}{\lambda } \\\ \end{aligned} (loge2=0.693)\left( {{\log }_{e}}2=0.693 \right)
We know that mean life (τ)\left( \tau \right) is the reciprocal of decay constant,
i.e.
τ=1λ λ=1τ t12=0.693λ t12=0.693τ \begin{aligned} & \tau =\dfrac{1}{\lambda } \\\ & \lambda =\dfrac{1}{\tau } \\\ & {{t}_{\frac{1}{2}}}=\dfrac{0.693}{\lambda } \\\ & {{t}_{\frac{1}{2}}}=0.693\tau \\\ \end{aligned}
This is the relation between half-life and mean life.
In this question the half-life of N13{{N}^{13}} is 10.1 minutes, and we have to find out its mean life.
From the expression,
t12=0.693τ 10.1=0.693τ τ=10.10.693 \begin{aligned} & {{t}_{\frac{1}{2}}}=0.693\tau \\\ & 10.1=0.693\tau \\\ & \tau =\dfrac{10.1}{0.693} \\\ \end{aligned}
Hence the mean life of N13{{N}^{13}} is 10.10.693\dfrac{10.1}{0.693} minutes.

Therefore option C. is the correct answer.

Note : The mean life of radioactive nuclei is nearly 42% more than that of half-life.
Students must always notice the question (in this case, the unit is minute). Sometimes the unit in the question and answer can be different. Don’t try to memorize all the formulas, always try to memorize the basic formula and the way of the derivation for the further formulas.