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Question

Chemistry Question on Chemical Kinetics

The half-life period of a radioactive element is 140 days. After 650 days, one gram of the element will reduce to

A

12g\frac{1}{2}g

B

14g\frac{1}{4}g

C

18g\frac{1}{8}g

D

116g\frac{1}{16}g

Answer

116g\frac{1}{16}g

Explanation

Solution

560 daya =560140=\frac{560}{140} =4 half-lives
Amount of reactant remaining after /z-half-lives
=(12)n×=\bigg(\frac{1}{2}\bigg)^n\times initial amount =(12)4×1.0g=116g=\bigg(\frac{1}{2}\bigg)^4\times1.0g=\frac{1}{16}g