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Question: The half-life period of a first order reaction is 100 sec. The rate constant of the reaction is...

The half-life period of a first order reaction is 100 sec. The rate constant of the reaction is

A

6.93×10−3sec⁡−16.93 \times 10^{- 3}\sec^{- 1}{}

B

6.93×10−4sec⁡−16.93 \times 10^{- 4}\sec^{- 1}{}

C

0.693 6musec⁡−10.693\mspace{6mu}\sec^{- 1}{}

D

69.3sec⁡−169.3\sec^{- 1}{}

Answer

6.93×10−3sec⁡−16.93 \times 10^{- 3}\sec^{- 1}{}

Explanation

Solution

k=0.693t1/2=0.693100 6musec⁡k = \frac{0.693}{t_{1/2}} = \frac{0.693}{100\mspace{6mu}\sec} =6.93×10−3sec⁡−1= 6.93 \times 10^{- 3}\sec^{- 1}{}