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Question

Chemistry Question on kinetics equations

The half life period of a first order chemical reaction is 6.93 minutes. The time required for the completion of 99% of the chemical reaction will be (log 2 = 0.301)

A

23.03 minutes

B

46.06minutes

C

460.6 minutes

D

230.03 minutes

Answer

46.06minutes

Explanation

Solution

For first order reaction,
k=0.693t1/2=0.6936.93k=\frac{0.693}{t_{1 /2} }=\frac{0.693}{6.93}
k=2.303tlog10010099k=\frac{2.303}{t} \, log\, \frac{100}{100-99}
0.6936.93=2.303tlog1001\frac{0.693}{6.93}=\frac{2.303}{t} log\, \frac{100}{1}
0.6936.93=2.303×2t\frac{0.693}{6.93}=\frac{2.303\times2}{t}
t=46.06 min