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Question: The half life of the reaction \(X \rightarrow Y\) following first order kinetics, when the initial c...

The half life of the reaction XYX \rightarrow Y following first order kinetics, when the initial concentration of a is 0.01molL10.01molL^{- 1} and initial rate is 0.00352molL1min10.00352molL^{- 1}\min^{- 1}{} will be

A

19.69min19.69\min

B

1.969min1.969\min

C

7.75min7.75\min

D

77.5min77.5\min

Answer

1.969min1.969\min

Explanation

Solution

dxdt=k[X]\frac{dx}{dt} = k\lbrack X\rbrack (For a first order reaction)

0.00352=k×0.01k=0.3520.00352 = k \times 0.01 \Rightarrow k = 0.352

t1/2=0.693k=0.6930.352=1.969min.t_{1/2} = \frac{0.693}{k} = \frac{0.693}{0.352} = 1.969min.