Question

The half-life of radioactive element is $600 \,yr$. The fraction of sample that would remain after $3000 \,yr$ is

• A. 44563
• B. 44577
• C. 44569
• D. Jan-32

Answer 1

Answer: (D)

Jan-32

Answer 2

We know that $n = \frac{1}{T}$ Given, $n =\frac{1}{T}$ $t =3000\, yr$ $T =600 \,yr$ $n =\frac{3000}{600}=5$ Then, $\frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{n}$ $\frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{5}=\frac{1}{32}$