The half-life of a radioactive element is (10 ,h). The fract... | Physics | SolveeIt | Solveeit

Today, August 18

Question

The half-life of a radioactive element is $10 \,h$ . The fraction of initial radioactivity of the element that will remain after $40\, h$ is

A

$\frac{1}{2}$

B

$\frac{1}{16}$

C

$\frac{1}{8}$

D

$\frac{1}{4}$

Answer

$\frac{1}{16}$

Explanation

Solution

After 4 half-lifes
$\frac{N_{0}}{2^{4}}=\frac{N_{0}}{16}$