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Question: The half-life of \(^{58}Co\) is 72 days. How many days does it take for \(3/4\) of the initial mass ...

The half-life of 58Co^{58}Co is 72 days. How many days does it take for 3/43/4 of the initial mass to disintegrate?
A. 144 days
B. 14 days
C. 140 days
D. 130 days

Explanation

Solution

We can see that two half lives have been covered (34=12+14)\left( {\dfrac{3}{4} = \dfrac{1}{2} + \dfrac{1}{4}} \right) . We know the time of one half life, so the time taken can be calculated.

Formula used:
The formula for the half life of a substance is
N=N0(12)tt1/2N = {N_0}{\left( {\dfrac{1}{2}} \right)^{\dfrac{t}{{{t_{1/2}}}}}}
where,
N=N = the initial amount of substance
N0={N_0} = amount of substance still remaining/ amount not yet decayed after time t
t1/2={t_{1/2}} = half-life of the substance

Complete step by step answer:
here we are given that 3/4 of the substance disintegrates, therefore, the remaining amount of substance is 1/4 th of original quantity. Let the original quantity be N, then the amount left is 1/4 N.
Also, the half life of given isotope of Cobalt is 72 days i.e t1/2=72days{t_{1/2}} = {72\,days}
Using the formula for half-life,

14N=N(12)t72 (12)2=(12)t72 2=t72 t=144days \dfrac{1}{4}N = N{\left( {\dfrac{1}{2}} \right)^{\dfrac{t}{{72}}}} \\\ \Rightarrow {\left( {\dfrac{1}{2}} \right)^2} = {\left( {\dfrac{1}{2}} \right)^{\dfrac{t}{{72}}}} \\\ \Rightarrow 2 = \dfrac{t}{{72}} \\\ \therefore t = {144\,days} \\\

Therefore, the answer is option A.

Additional information:
The half-life of a radioactive substance is a characteristic constant. It measures the time it takes for a given amount of the substance to become reduced by half as a consequence of decay, and therefore, the emission of radiation.Archeologists and geologists use half-life to date the age of organic objects in a process known as carbon dating. During beta decay, carbon 14 becomes nitrogen 14. At the time of death organisms stop producing carbon 14. Since half life is a constant, the ratio of carbon 14 to nitrogen 14 provides a measurement of the age of a sample.

Note: We can also simply see that 3/4 of the original amount will disintegrate after 2 half lives because one half life means 1/2 of the substance and 1/4 means the second half life. And two half lives mean two times the half-life period. 72x2=144days