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Question: The half cycle of a radioactive nucleus is 50 days. The time interval \(({{t}_{2}}-{{t}_{1}})\) betw...

The half cycle of a radioactive nucleus is 50 days. The time interval (t2t1)({{t}_{2}}-{{t}_{1}}) between the time t2{{t}_{2}} when 23\dfrac{2}{3}of it has decayed and the time t1{{t}_{1}} when 13\dfrac{1}{3}of it has decayed is
A. 50 days
B. 60 days
C. 15 days
D. 30 days

Explanation

Solution

First let us learn what half-life or half cycle of a radioactive substance means. Half-life in radioactivity is the interval of time required for one half of a NNo=(12)tT\dfrac{N}{{{N}_{o}}}=\,{{\left( \dfrac{1}{2} \right)}^{\dfrac{t}{T}}} atomic nuclei of a radioactive sample to decay. To solve the above question, we need to use the formula given, since the time is mentioned. There is another formula for half-life you can use, t12=ln(2)k{{t}_{\dfrac{1}{2}}}=\,\dfrac{\ln (2)}{k} where t12{{t}_{\dfrac{1}{2}}} is the half life and k is the decay constant.

Complete step by step answer:
Let us perform the solution stepwise now.
When time is t 2
Number of decayed nuclei =23=\dfrac{2}{3}
So, number of undecayed nuclei (123)att2(1-\dfrac{2}{3})\,at\,\,{{t}_{2}}
=13(NNo)=\,\,\dfrac{1}{3}\,\left( \dfrac{N}{{{N}_{o}}} \right)
Again, when time is t 1
Number of decayed nuclei =13=\dfrac{1}{3}
So, number of undecayed nuclei (113)(1-\dfrac{1}{3})\,at t1
=23(NNo)=\,\,\dfrac{2}{3}\,\left( \dfrac{N}{{{N}_{o}}} \right)
At time t 2 13=(12)t2T\dfrac{1}{3}\,=\,{{\left( \dfrac{1}{2} \right)}^{\dfrac{{{t}_{2}}}{T}}} eq. (1) [Using the formula NNo=(12)tT\dfrac{N}{{{N}_{o}}}=\,{{\left( \dfrac{1}{2} \right)}^{\dfrac{t}{T}}}]
At time t 123=(12)t1T\dfrac{2}{3}=\,{{\left( \dfrac{1}{2} \right)}^{\dfrac{{{t}_{1}}}{T}}} eq. (2)
Now, we divide equation 1 by equation 2
1323=(12)(12)ttTt2T\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\,=\,{{\dfrac{\left( \dfrac{1}{2} \right)}{{{\left( \dfrac{1}{2} \right)}^{\,\dfrac{{{t}_{t}}}{T}}}}}^{\dfrac{{{t}_{2}}}{T}}}
12=(12)t2t1T\Rightarrow \dfrac{1}{2}={{\left( \dfrac{1}{2} \right)}^{\dfrac{{{t}_{2}}-{{t}_{1}}}{T}}}
Since, the boxes are equal, we can compute both the powers,
1=t2t1T1=\dfrac{{{t}_{2}}-{{t}_{1}}}{T} (Now as you already know, T is the half-life, which is given as 50 in the question)
t2t1=50{{t}_{2}}-{{t}_{1}}=50 (putting T=50)
Therefore, the time interval t2t1{{t}_{2}}-{{t}_{1}} is equal to 50.

Thus, Option A is correct.

Note:
As you can see the half-life of a process is an indication of how fast that process proceeds- a measure of rate or capacity of the process. Also you can say it is the time taken by a substance to diminish to one half of its initial amount. Students must remember that radioactive decay is a process that occurs in an unstable atomic nucleus. If you solve more such problems you will get a better idea about it.