Question
Question: The \({H_3}P{O_4}\) is a tribasic acid and one of its salt is \(Na{H_2}P{O_4}\) . What volume in ml ...
The H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume in ml of 1M NaOH solution should be added to 12g of NaH2PO4 to convert into Na3PO4 ?
Solution
For solving the question numerically first we should know and write the chemical reaction which is required for the formation of Na3PO4 from NaH2PO4 . Quantify the amount of reactant required for the reaction to complete and then quantify them with the amount of reactant we are given to find the required volume of 1M NaOH .
Complete step by step answer:
As it is given in the question that H3PO4 is a tribasic acid which means it can replace its three hydrogen atoms. Phosphoric acid acts as an oxidizing agent. It is also called orthophosphoric acid mainly to distinguish it from other phosphoric acids. The oxidation state of phosphoric acid is +5 . So first let us write down the reaction which is required for formation of Na3PO4 .
NaH2PO4+2NaOH→Na3PO4+H2O
If we look at the above reaction we can observe that 1M of NaH2PO4 is required for 2M of NaOH .
First let us write the molar mass of NaH2PO4 which is 120g/mol . So the number of moles in 12g of NaH2PO4 will be 0.1mol.
Therefore the number of moles of NaOH required for the reaction =2×0.1mol=0.2mol .
As we know the molarity of NaOH is 1mol/L , so volume of 1mol NaOH=1L .
Therefore volume of 0.2mol NaOH=1×0.2L=0.2L=0.2×1000mL=200mL
So 200mL of 1M NaOH is to be added to 12g of NaH2PO4 to convert into Na3PO4 .
Note:
Phosphoric acid is soluble in alcohol as well as in water. It forms orthophosphate salts by replacing its hydrogen atoms with other positive ions. It is used for making fertilizers by forming phosphate salts. It is also used in the textile industry, dental cements and sugar industry. It is formed by the reaction of sulfuric acid with natural phosphate rock. This reaction also gives calcium sulfate also known as gypsum.