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Question: The ground state energy of hydrogen atom is –13.6 eV. Find the potential energy of electron (in Joul...

The ground state energy of hydrogen atom is –13.6 eV. Find the potential energy of electron (in Joule) in the given state.

A

−4.36×10−14 J- 4.36 \times 10^{- 14}\text{ J}

B

−4.36×10−16 J- 4.36 \times 10^{- 16}\text{ J}

C

−4.36×10−17 J- 4.36 \times 10^{- 17}\text{ J}

D

−4.36×10−18 J- 4.36 \times 10^{- 18}\text{ J}

Answer

−4.36×10−18 J- 4.36 \times 10^{- 18}\text{ J}

Explanation

Solution

As, P.E. = -2K.E.

Here, K.E. =13.6eV=2.18×10−18J= 13.6eV = 2.18 \times 10^{- 18}J

Hence, P.E. =−2×2.18×10−18J= - 2 \times 2.18 \times 10^{- 18}J

=−4.36×10−18J= - 4.36 \times 10^{- 18}J