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Question: The ground state energy of hydrogen atom is\(- 13.6\text{ eV.}\) The kinetic energy of the electron ...

The ground state energy of hydrogen atom is−13.6 eV.- 13.6\text{ eV.} The kinetic energy of the electron in this state is

A

2.18×10−14 J2.18 \times 10^{- 14}\text{ J}

B

2.18×10−16 J2.18 \times 10^{- 16}\text{ J}

C

2.18×10−18 J2.18 \times 10^{- 18}\text{ J}

D

2.18×10−19 J2.18 \times 10^{- 19}\text{ J}

Answer

2.18×10−18 J2.18 \times 10^{- 18}\text{ J}

Explanation

Solution

Here the ground state energy, (E) =−13.6eV= - 13.6eV

Since ,K.E. of the electron = −E=13.6eV- E = 13.6eV

=13.6×1.6×10−19J= 13.6 \times 1.6 \times 10^{- 19}J

=21.76×10−19J= 21.76 \times 10^{- 19}J

=2.18×10−18J= 2.18 \times 10^{- 18}J