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Question

Question: The grid voltage of any triode valve is changed from –1 volt to – 3 volt and the mutual conductance ...

The grid voltage of any triode valve is changed from –1 volt to – 3 volt and the mutual conductance is 3×1043 \times 10^{- 4}mho. The change in plate circuit current will be

A

0.8 mA

B

0.6 mA

C

0.4 mA

D

1 mA

Answer

0.6 mA

Explanation

Solution

By using gm=ΔipΔvgg_{m} = \frac{\Delta i_{p}}{\Delta v_{g}}3×104=Δip1(3)3 \times 10^{- 4} = \frac{\Delta i_{p}}{- 1 - ( - 3)}

Δip=6×104A=0.6mA\Delta i_{p} = 6 \times 10^{- 4}A = 0.6mA