Question

The gravitational force between force and objects is ‘$F$’. How will this force change when?
(i) Distance between objects is halved.
(ii) Mass of 2 objects is quadrupled.

Answer 1

To answer this question, we first need to understand what is gravitational force. Gravity, often known as gravitation, is the universal force of attraction that acts between all matter in mechanics. It is the weakest known force in nature, and so has no bearing on the interior properties of ordinary matter.

Complete step by step answer:
Gravity, or gravitation, is a natural phenomenon that causes all things with mass or energy to gravitate toward one another, including planets, stars, galaxies, and even light. Gravity gives tangible items weight on Earth, and the Moon's gravity creates ocean tides.Gravitational force formula,
$F = G\dfrac{{{M_1}{M_2}}}{{{R^2}}}$
Here $G$ is the gravitational constant with value equal to $6.674 \times {10^{ - 11}}{m^3}K{g^{ - 1}}{s^{ - 2}}$ $and{\kern 1pt} {\kern 1pt} {\kern 1pt} {M_1},{M_2}$ are the masses of the two objects and $R$ is the distance between them.

(i) In this case – as we know that gravitational force is inversely proportional to the square of distance as given in the formula. So, when the distance is halved, the gravitational force will be 4 times the original. So, the final value of force is $4F$.
(ii) In this case – as we know that gravitational force is directly proportional to the product of masses as given in the formula. So, when the masses are quadrupled, the gravitational force will be 16 times the original. So, the final value of force is $16F$.

Note: Any object in the earth's gravitational field receives a gravitational attraction.Gravitational acceleration is the acceleration that an object experiences as a result of the force of gravity acting on it. The symbol for it is ‘$g$,' and the unit is $m{s^{ - 2}}$. The amount and direction of gravitational acceleration are both vector quantities.