Question

The gravitational force between a H - atom and another particle of mass m will be given by Newton’s law:

$F = G\frac{M.m}{r^{2}}$ where r is in km and

• A. $M = m_{proton} + m_{electron}$
• B. $M = m_{proton} + m_{electron} - \frac{B}{c^{2}}(B = 13.6eV)$
• C. M is not related to the mass of the hydrogen atom
• D. M= $m_{protorn} + m_{electron} - \frac{|V|}{c^{2}}(|V| = magnitudeof)$ the potential energy of electron in the H - atom

Answer 1

Answer: (B)

$M = m_{proton} + m_{electron} - \frac{B}{c^{2}}(B = 13.6eV)$

Answer 2

: Here , M = Mass of hydrogen atom

$= m_{proton} + m_{electron} - \frac{B}{c^{2}}$

Where b is binding energy of H-atom which is $13.6$eV