Question

The gravitational field due to a mass distribution is given by I = (A/x³) in X-direction. The gravitational potential at a distance x is equal to

• A. –$\frac { A } { x ^ { 3 } }$
• B. – $\frac { A } { 2 x ^ { 2 } }$
• C. –$\frac { A } { x ^ { 4 } }$
• D. $\frac { A } { 2 x ^ { 2 } }$

Answer 1

Answer: (D)

$\frac { A } { 2 x ^ { 2 } }$

Answer 2

The potential at a distance x is

V(x) = - = –

V(x) = $\left[ \frac { \mathrm { A } } { 2 \mathrm { x } ^ { 2 } } \right] _ { \infty } ^ { \mathrm { x } }$ =

⇒ Therefore (4).