Question

The gravitational field due to a mass distribution is $E = K / x ^ { 3 }$in the x - direction (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is

• A. $K / x$
• B. $K / 2 x$
• C. $K / x ^ { 2 }$
• D. $K / 2 x ^ { 2 }$

Answer 1

Answer: (D)

$K / 2 x ^ { 2 }$

Answer 2

$V = - \int E d x$ $= \frac { K } { 2 x ^ { 2 } }$.