Question

The graph which shows the variation of $\big(\frac{1}{\lambda^2} \big)$and its kinetic energy, is $E$ (where $λ$ is de Broglie wavelength of a free particle):

• A.
• B.
• C.
• D.

Answer 1

Answer: (D)

Answer 2

Using $\lambda = \frac{h}{\sqrt{2mE}}$, we find $\frac{1}{\lambda^2} \propto E$, yielding a linear graph.