Question

The graph of $\log \frac{x}{m}$ vs $\log p$ for an adsorption process is a straight line inclined at an angle of $45^{\circ}$ with intercept equal to $0.6020$ The mass of gas adsorbed per unit mass of adsorbent at the pressure of $04 \,atm$ is______ $\times 10^{-1}$ (Nearest integer)
Given: $\log 2=0.3010$

Answer 1

The correct answer is 16.

logmx​=logk+n1​logP
n1​=tan45∘=1
logk=0.6020=log4
⇒K=4
∴mx​=K⋅P1/n
mx​=4(0.4)=1.6
mx​=1.6=16×10−1