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Question: The graph of line \(y = 6\) is a line that is: A.Parallel to the \(x\)axis at a distance of 6 unit...

The graph of line y=6y = 6 is a line that is:
A.Parallel to the xxaxis at a distance of 6 units from the origin.
B.Parallel to yyaxis at a distance of 6 units from the origin
C.Making an intercept of 6 units on the xxaxis
D.Making an intercept of 6 units on the both the axes

Explanation

Solution

Hint: Hint: The equation y=6y = 6 can be written as y=0x+6y = 0x + 6. Find the value of yy for different values of xx such as 1,0,1,2.. - 1,0,1,2... Then draw the line in the xyxy plane.

Complete step-by-step answer:
The equation given to us in the question y=6y = 6 can be rewritten as y=0x+6y = 0x + 6.
We can then find different ordered pair that satisfies the equation y=0x+6y = 0x + 6 by finding the different values of yy for different integer values of xx such as 1,0,1,2.. - 1,0,1,2..
Forx=0x = 0, y=6y = 6
x=1x = 1, y=6y = 6
x=2x = 2, y=6y = 6
x=3x = 3, y=6y = 6

The different ordered pairs so formed are(0,6),(1,6),(2,6),(3,6)\left( {0,6} \right),\left( {1,6} \right),\left( {2,6} \right),\left( {3,6} \right).

We can draw the line in the xyxy plane by plotting different points and joining them to form the line.

From the diagram we can observe that the line never touches the xx axis.
Therefore there is no intercept on the xx axis. Since there is no intercept on the xx axis the given line is parallel to the xx axis.
Also, we can observe that the distance between the xx axis and the given line is 6 units throughout.

Therefore we can conclude the given line is parallel to xx axis at a distance of 6 units from the origin.
Thus, option A is the correct answer.

Note: The graph of any equation of one variable can be plotted on the xyxy plane. The xx axis is the horizontal axis and yy axis is the vertical axis. The intersection of xx and yy axis is called the origin