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Question

Physics Question on Motion in a straight line

The graph of an object�s motion (along the x-axis) is shown in the figure. The instantaneous velocity of the object at points AA and BB are vAv_A and vBv_B respectively. Then

A

vA=vB=0.5m/sv_A = v_B = 0.5\,m/s

B

vA=0.5m/s<vBv_A = 0 .5\,m/s < v_B

C

vA=0.5m/s>vBv_A = 0 .5\,m/s > v_B

D

vA=vB=2m/sv_A = v_B = 2\,m/s

Answer

vA=vB=0.5m/sv_A = v_B = 0.5\,m/s

Explanation

Solution

Instantaneous velocity v=ΔxAΔtA=4m8s=0.5m/sv=\frac{\Delta x_{A}}{\Delta t_{A}}=\frac{4m}{8s}=0.5\,m/s and vB=ΔxBΔtB=8m16s=0.5m/sv_{B}=\frac{\Delta x_{B}}{\Delta t_{B}}=\frac{8m}{16s}=0.5\,m/s i.e., vA=vB=0.5m/sv_{A}=v_{B}=0.5\,m/s