Question

The graph between two temperature scales $P$ and $Q$ is shown in the figure Between upper fixed point and lower fixed point there are 150 equal divisions of scale $P$ and 100 divisions on scale $Q$ : The relationship for conversion between the two scales is given by:-

• A. $\frac{t_P}{100}=\frac{t_Q-180}{150}$
• B. $\frac{t_Q}{150}=\frac{t_P-180}{100}$
• C. $\frac{t_p}{180}-\frac{t_Q-40}{100}$
• D. $\frac{t_Q}{100}=\frac{t_P-30}{150}$

Answer 1

Answer: (D)

$\frac{t_Q}{100}=\frac{t_P-30}{150}$

Answer 2

The correct answer is (D) : $\frac{t_Q}{100}=\frac{t_P-30}{150}$
upper fixed po int-lower fixed point reading on scale − Lower fixed point ​= constant
180−30tp​−30​=100−0tQ​−0​
150tp​−30​=100tQ​​