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Question

Question: The gradient of the radical axis of the circles \(x ^ { 2 } + y ^ { 2 } - 3 x - 4 y + 5 = 0\) and ...

The gradient of the radical axis of the circles x2+y23x4y+5=0x ^ { 2 } + y ^ { 2 } - 3 x - 4 y + 5 = 0 and 3x2+3y27x+8y+11=03 x ^ { 2 } + 3 y ^ { 2 } - 7 x + 8 y + 11 = 0 is

A

13\frac { 1 } { 3 }

B

110- \frac { 1 } { 10 }

C

12- \frac { 1 } { 2 }

D

23- \frac { 2 } { 3 }

Answer

110- \frac { 1 } { 10 }

Explanation

Solution

Equation of radical axis is S1S2=0S _ { 1 } - S _ { 2 } = 0

S1x2+y23x4y+5=0S _ { 1 } \equiv x ^ { 2 } + y ^ { 2 } - 3 x - 4 y + 5 = 0, S2x2+y273x+8y3+113=0S _ { 2 } \equiv x ^ { 2 } + y ^ { 2 } - \frac { 7 } { 3 } x + \frac { 8 y } { 3 } + \frac { 11 } { 3 } = 0

\therefore Radical axis is 2x20y+4=0- 2 x - 20 y + 4 = 0.

Hence, gradient of radical axis = 110- \frac { 1 } { 10 }