Question

The given square is drawn in uniform electric field. If potential at the corners A, B, C, D are 5 V, 10 V, 15 V & 10 V respectively and at centre potential is 10 V, then the magnitude of electric field is–

• A. 5 V/m
• B. 10 V/m
• C. $5\sqrt{2}$ V/m
• D. 500 V/m

Answer 1

Answer: (D)

500 V/m

Answer 2

Q V_B = V_D = V_­E = 10 V

\ line BD is equipotential surface

\ electric field will be perpendicular to line BD

\ E = $\frac { \Delta \mathrm { V } } { \mathrm { d } }$ = $\frac { ( \Delta \mathrm { V } ) _ { \mathrm { EA } } } { \mathrm { d } }$ = $\frac { 10 - 5 } { \frac { \sqrt { 2 } } { \sqrt { 2 } } \times 10 ^ { - 2 } }$ = 500 V/m